28=(t^2-t)/2

Solution for 28=(t^2-t)/2 equation:

28=(t^2-t)/2

We move all terms to the left:

28-((t^2-t)/2)=0

We multiply all the terms by the denominator


-((t^2-t)+28*2)=0


We calculate terms in parentheses: -((t^2-t)+28*2), so:

(t^2-t)+28*2

We add all the numbers together, and all the variables

(t^2-t)+56

We get rid of parentheses

t^2-t+56

We add all the numbers together, and all the variables

t^2-1t+56

Back to the equation:

-(t^2-1t+56)


We get rid of parentheses

-t^2+1t-56=0

We add all the numbers together, and all the variables

-1t^2+t-56=0

a = -1; b = 1; c = -56;
Δ = b2-4ac
Δ = 12-4·(-1)·(-56)
Δ = -223
Delta is less than zero, so there is no solution for the equation